GVC736CE101 3BHE039203R0101 5SXE12-0184 system in the mechanical parameters set up, first of all, according to the substrate scribing data for programming, to determine the scribing data, MARK point data, the number of knives used, each knife scribing each line pressure, scribing, and so on, the above parameters have a special software to edit. After editing is completed and then through the PC1 input PLC CPU, in the completion of the data editing, the software back to automatically generate a cutting simulation screen to determine the substrate scribing of each step by which a few knives to do, in the completion of this series of work, it is necessary to put the substrate into the trial scribing.

GVC736CE101 3BHE039203R0101 5SXE12-0184 according to the system settings, in the substrate into the substrate after pressing the start button, the substrate platform will automatically send the substrate to the image processing system of the CCD below the top of the monitor to see the above, as shown in Figure 4, in the MARK recognition and the system settings there will be a deviation, according to the deviation system to make up the correction. Correction, now introduces the correction process, such as Figure 7, to the first knife, for example, the knife 1 origin and the CCD origin of the X distance D1 in the system is set to a certain value, the knife 1 and the knife 1 origin of the distance D2 in the preparation of the programme is generated, but also for a certain value.

GVC736CE101 3BHE039203R0101 5SXE12-0184 origin and now the distance between the CCD D3, in the preparation of the programme there is a MARK coordinate value, D3 that is, for the substrate of the X direction MARK coordinates, D4 for the MARK point and the knife 1 scratch the substrate of the first line of the X direction distance, in the ideal state for a certain value. That is, it can be concluded that D1 + D2 = D3 + D4, of which D1, D2 is a fixed value, assuming that D5 for the CCD to identify the dynamic coordinates of the MARK point, the deviation correction for the △ d, it can be concluded that D5 = D3 ± △ d